1) Give an example of a biased survey question online. Include a link to the question or a citation to show where the question was found . This question should have been written in the last year.2) Why the question is biased. Refer to the video or your textbook as to what type of bias the question is exhibiting.In your response:3)”What makes our service delivery stand out for you?”. Rewrite the biased question so that it is not biased.

An enthusiastic sports fan decides to express his support for his team by betting on it, and eventually making some

An enthusiastic sports fan decides to express his support for his team by betting on it, and eventually making some profit out of that enjoyable activity.He knows from past statistics that the probability of his team winning in a given match is 0.75, and the probability of losing is 0.25 (let us ignore other possible outcomes). -He gets $12 if his team wins. How much should he be willing to pay. If his team loses, in order to make and average profit of $2 per bet? -He pays $15 beforehand, and if his team wins he receives $20. What is his expected gain from his bet? [1,2.5.2]

I need help with the following question in regards to the research below. Thank you Discuss briefly the assumptions and

I need help with the following question in regards to the research below. Thank you Discuss briefly the assumptions and limitations that apply to ANOVA.Researchers wanted to determine the effects of exercise on stress. They divided a random sample into groups, with each group having a specified level of exercise. A pretest of stress levels was given to all participants to establish a baseline. One group had strenuous exercise, another had moderate exercise, and another was the control group which had no exercise. After the exercise period, a posttest was given to measure the stress level. The scores for comparison were calculated by subtracting the baseline stress measurement from the final stress measurement. Here is the ANOVA table with the results: Source SS df MS F p Between 4,689.27 2 2,344.635 0.7664 >.05 Within 82,604.20 27 3,059.415 Total 87,293.47 29

The probability of success is 0.625. A sample of 752 is taken.What is the mean of the population distribution? What

The probability of success is 0.625. A sample of 752 is taken.What is the mean of the population distribution? What is the standard deviation of the population proportion?What is the mean of the k sampling distribution?What is the standard error of the k sampling distribution?What is the probability of getting more than 483 successes?What is the standard error of the proportion sampling distribution?What is the probability of getting a proportion of less than 0.58?Based on the population proportion, 95% of all samples have a proportion between:

1. What is the probability of obtaining a test score above 90 for a distribution with a M = 78

Religion and Theology Assignment Writing Service1. What is the probability of obtaining a test score above 90 for a distribution with a M = 78 and an SD = 7.50 a. First compute the z-score for a score of 90 by completing the transformation equation below: z = (x – M) / SD z = z =

Preventable chronic diseases are increasing rapidly in some regions, particularly diabetes. Shown below is a contingency table showing cross classification

Preventable chronic diseases are increasing rapidly in some regions, particularly diabetes. Shown below is a contingency table showing cross classification of educational attainment and diabetic state for a random sample of 1429 people in a region (HS is high school). At the 1% significance level, do the data provide sufficient evidence to conclude that an association exists between educational level and diabetic state for the region

I have the answers, just need to understand how to get them. Thank you! You are making the sourcing decisions

I have the answers, just need to understand how to get them. Thank you! You are making the sourcing decisions for a fashion company and it turns out that there are two options for manufacturing your “Punk Rock Operations” T-shirts. You sell the T-shirts for $15 each during the two months of December and January right after you get the results of BUAD-311. Given that the grading of 311 is so unpredictable, the demand of these T-shirts is also unpredictable, with the mean over the two months being 500 and the standard deviation being 150. Any leftover shirts are donated to charity. The first option is to outsource the production in China, in which case the procurement cost of each T-shirt is $5, the shipping cost is $200 (regardless of the size of the order) and it takes 2 months for the order to be delivered. Alternatively, you can produce in Los Angeles where the procurement cost goes up to $10 but the lead time is just one day. The fixed printing cost for the LA shop is $30. The financing cost for each T-shirt is $2 per T-shirt per year. For reference, here is a sample of potentially useful standard normal Z-table values: Z value: 0.0 0.433 0.675 0.84 1.04 1.28 1.65 2.05 Probability: 50% 66.7% 75% 80% 85% 90% 95% 98% Assuming that students that do not receive a shirt are forgiving and quickly move on, what is your optimal order quantity if you decide to outsource to China? Answer should be 565 T-shirts. What is your total cost if you decide to outsource? Answer should be $3,130 What is the probability of stocking out if you decide to outsource? Answer should be 33.3% What is your optimal order quantity if you decide to manufacture in Los Angeles? Answer should be 300 shirts What is your Reorder Point if you decide to manufacture in Los Angeles if you want to achieve the same stock-out probability as the outsourcing option? Answer should be 16.7183 What is your total cost if you decide to manufacture in Los Angeles? Answer should be $5,102.79

Compare the variation in heights to the variation in weights of thirteen-year old girls. The heights (in inches) and weights

Compare the variation in heights to the variation in weights of thirteen-year old girls. The heights (in inches) and weights (in pounds) of nine randomly selected thirteen-year old girls are listed below.(Heights (inches): 58.7 61.4 62.1 64.7 60.1 58.3 64.6 63.7 66.1)(Weights (pounds): 89 97 93 119 96 90 123 98 139)

[Calculating Probability from Data] The table below gives details of symptoms that patients presented and whether they were suffering from

[Calculating Probability from Data] The table below gives details of symptoms that patients presented and whether they were suffering from meningitis. ID Headache Fever Vomiting Meningitis 1 True True False False 2 False True False False 3 True False True False 4 True False True False 5 False True False True 6 True False True False 7 True False True False 8 True False True True 9 False True False False 10 True False True True Using this dataset, calculate the following probabilities : a) P(Vomiting = true) b) P(Headache = false) c) P(Headache = true AND Vomiting = false) d) P(Meningitis = false | Fever = true AND Vomiting = false)

I recently worked this problem for a practice quiz and I got the problem wrong. Can you please show a

I recently worked this problem for a practice quiz and I got the problem wrong. Can you please show a step-by-step solution (without Excel) so I can see where I went wrong?A statistics course has 21 students in which 70% passed. At 95% confidence, the upper confidence limit for the proportion students passing with 3 decimal places is

Imagine you are in charge of putting an anti-smoking communication campaign together (geared towards young adults) in your local community.

Imagine you are in charge of putting an anti-smoking communication campaign together (geared towards young adults) in your local community. Correctly identifying your target audience would be an important step. Who would be your target audience or audiences in this example? Are there any groups or sub-groups? Also, would you need to segment your audience in any way? Please address each of these questions and explain the overall importance of correctly identifying your target audience as part of your intended communication campaign.

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