Home » 1- Which of these variables are independent (IV) and dependent variables (DV)?a. IV: Disability typeDV: Rate of learning disabilitiesb .IV:

# 1- Which of these variables are independent (IV) and dependent variables (DV)?a. IV: Disability typeDV: Rate of learning disabilitiesb .IV:

1- Which of these variables are independent (IV) and dependent variables (DV)?a. IV: Disability typeDV: Rate of learning disabilitiesb .IV: Urban areas, type of disability being the blocking variable DV: Rate of learning disabilities c. IV: Rate of learning disabilitiesDV: Disability type and urban areasd. IV: Urban areasDV: Disability type and rat2- What type of study design was used in this study and why? a. One-Way ANOVA because there is only one independent variableb. Two-Way ANOVA because there are two independent variablesc. Blocking design that involves one main independent variable and a blocking variabled. Blocking design that involves a blocking variable with one dependent variable3- What is the blocking variable? What is the purpose of the blocking variable in this study?a. Type of disability. The purpose is to control for potential effects of an additional variable such as disability type on the outcome in order to determine the true effect of the main independent variable (urban areas) on the rate of learning disabilities.b. Urban areas is the blocking variable. The purpose of including a blocking variable such as urban areas is to control for potential confounding between the disability type and rate of learning disabilities.c. None of the above is correct. 4- What can you conclude about the significance of the urban areas variable effects at α = 0.05. Draw appropriate conclusions?a. There is sufficient evidence to reject the null hypothesis since p-value

From the U.S. Department of Transportation, National Highway Traffic Safety Administration; Federal Highway Administration, we learn that 11.6% of all
From the U.S. Department of Transportation, National Highway Traffic Safety Administration; Federal Highway Administration, we learn that 11.6% of all drivers are under the age of 25 and 37.3% of all drivers are over the age of 55. Drivers under age 25 have a probability of being involved in a fatal crash of 18.4%. Drivers between the ages of 25 and 55 have a probability of being involved in a fatal crash of 51.9%. Drivers over the age of 55 have a probability of being involved in a fatal crash of 29.7%. (By the way, those are the most recent yearly numbers as pulled from their website three weeks ago.) Let F = involved in a fatal crash. Show all work.a) What is the probability of being involved in a fatal crash? [In other words, find P(F)]b) Given that a driver was involved in a fatal crash, what is the probability that person was under the age of 25?c) Given that a driver was involved in a fatal crash, what is the probability that person was between the ages of 25 and 55?d) Given that a driver was involved in a fatal crash, what is the probability that person was over the age of 55?

For each problem that requires you to use your calculator, please write the calculator command you are using in order
For each problem that requires you to use your calculator, please write the calculator command you are using in order to receive full credit. For example: normalcdf(4,5,7,1)=.02. Don’t just state the value you get from your calculator. Unless otherwise stated in the problem, round answers to 4 decimal places.

Consider a similar experiment where each of 10 volunteer participants tastes both types of fries. Assume that there are a
Consider a similar experiment where each of 10 volunteer participants tastes both types of fries. Assume that there are a total of 10 volunteer participants and that each row in Table 1 now represents the ratings from a single participant for the two brands of fries. {Assume that the order of tasting was counterbalanced such that half the participants tasted McDonald’s fries first and the other half tasted Burger King’s first.} Create new data file for this within-subject experiment and use SPSS to run the appropriate t-test. (7) Paste the output of your t-test here. (8) Are the mean tastiness ratings the same in this analysis as they were for the between-subjects analysis? What is the difference between the two means in this analysis? (9) Is the standard error of the “mean difference” the same in both analyses? {Alert! The standard error of the mean difference is found, in each analysis, in the last output box labeled “independent samples test” and “paired samples test”, respectively. This standard error is not the same as the standard error associated with the mean for McDonalds or with the mean for Burger King. (10) Are the obtained t statistics the same in both analyses? (11) Why are they different? {Consider your answer to #9.} (12) In terms of size, there is a fairly large correlation between the paired samples. What does this tell you? use this to answer the questions:

Use the sample information x¯x¯ = 36, σnμ (a) The 90% confidence interval is from to (b) = 6, =
Religion and Theology Assignment Writing ServiceUse the sample information x¯x¯ = 36, σnμ (a) The 90% confidence interval is from to (b) = 6, = 11 to calculate the following confidence intervals for assuming the sample is from a normal population. 90 percent confidence. (Round your answers to 4 decimal places.)95 percent confidence. (Round your answers to 4 decimal places.)The 95% confidence interval is from to (c) 99 percent confidence. (Round your answers to 4 decimal places.) The 99% confidence interval is from to

Assignment ContentUsing G*Power and the information provided, answer the following:Problem 1:To what extent does age, race, and gender predict the

Given P(X) = 0.5, P(Y) = 0.4, and P(Y|X) = 0.3, what are P(X and Y) and P(X or Y)?
Given P(X) = 0.5, P(Y) = 0.4, and P(Y|X) = 0.3, what are P(X and Y) and P(X or Y)? a P(X and Y) = 0.9, P(X or Y) = 0.75 bP(X and Y) = 0.9, P(X or Y) = 0.1 cP(X and Y) = 0.15, P(X or Y) = 0.75 dP(X and Y) = 0.75, P(X or Y) = 0.15 eP(X and Y) = 0.15, P(X or Y) = 0.1

I have a data analysis for a statistic class, and I need help on part 3 on the calculation and
I have a data analysis for a statistic class, and I need help on part 3 on the calculation and the discussion of these results.Develop and discuss in the context of the problem the 95% confidence interval estimates for absentees from work (ABSENT) fora. all employees; b. employees from each job complexity categories; c. employees from each supervisor satisfaction categories.My results are: a. We are 95% confident that the number of absenteeism for all employees ranges from [0.4143, 0.8000] for 0 to 1 occasion, [2, 2] for 2 occasions, and [3.2364, 3.9779] occasions. b. We are 95% confident that the employees from each job complexity category ranges from [9.7890, 16.1465] for low complexity, [53.4641, 61.1645] for standard complexity, and [76.9235, 82.5310] for high complexity. c. We are also 95% confident that the satisfaction level of employees from each supervisor satisfaction category ranges from [0.3586, 0.6803] and the dissatisfaction level ranges from [0.3518, 0.6872].The calculation that I did, did not have a correlation with the other parts that my teammates have for Part 1, 2

Neurons fire action potentials (spikes) at different frequencies under different circumstances. In one study, researchers position an awake-behaving monkey so
Neurons fire action potentials (spikes) at different frequencies under different circumstances. In one study, researchers position an awake-behaving monkey so that he or she is looking at a luminous dot 40 cm away, and they record the activity of a single neuron in the monkey’s brain to determine the neuron’s baseline. Over the course of 74 trials randomly interspaced with other conditions, that neuron is found to have an average baseline of =28.2 spikes per second with a standard deviation of s=31.5 spikes per second.What is the standard error of the sample mean, SE, in spikes per second? Give your answer to two decimal places.

Based on your sample, you will conduct a hypothesis test with to test two of the claims of the above
Based on your sample, you will conduct a hypothesis test with to test two of the claims of the above article. Using the same sheet as last week, answer the following in the “week 6” tab:Claim: the average age of online students is 32 years old.What is the null hypothesis?What is the alternative hypothesis?What distribution should be used?What is the test statistic?What is the p-value?What is the conclusion?Claim: the proportion of males in online classes is 35%What is the null hypothesis?What is the alternative hypothesis?What distribution should be used?What is the test statistic?What is the p-value?What is the conclusion?

a) mean of 120.1 mmHgstandard deviation of 15.1 mmHgb)What proportion of the population has a blood pressure that is below
a) mean of 120.1 mmHgstandard deviation of 15.1 mmHgb)What proportion of the population has a blood pressure that is below the value 101.3 mmHg for a normally-distributed set of blood pressures with a and a ? Express the answer as a percentage rounded off to 1 decimal place.What percentage of the population would have a blood pressure higher than this value? Express the answer as a percentage rounded to 1 decimal place

In the United States, according to a 2018 review of National Centerfor Health Statistics information, the average age of a
In the United States, according to a 2018 review of National Centerfor Health Statistics information, the average age of a mother when her first child is born in the U.S. is 26 years old. A curious student at CBC has a hypothesis that among mothers at community colleges, their average age when their first child was born is greater than the national average. To test her hypothesis, she plans to collect a random sample of CBC students who are mothers and use their average age at first childbirth to determine if the CBC average is greater than the national average.Use the dropdown menus to setup this study as a formal hypothesis test.Ho: {Select} 26Ha: {Select} 26

Student A has a sample { X1, X2, …….,X20} with Mean X20= 5.3 andStandard dev= 1.6. Student B has a
Student A has a sample { X1, X2, …….,X20} with Mean X20= 5.3 andStandard dev= 1.6. Student B has a sample { Y1, Y2, …….,Y35} with Mean Y35= 6.2 and Standard dev= 2.9.Put these two samples together you have { X1, X2, …….,X20, Y1, Y2, …….,Y35}. Find mean and SD of this pooled data.

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